program for checking number of vowels in a string
/*
as we know that there is 5 vowels in our english alphabets.
such as "a,e,i,o,u";
*/
#include<iostream.h>
#include<conio.h>
int main()
{
char ch[25];
int i,l=0;
cout<<"Enter a string:\n";
cin.getline(ch,25);
for(i=0;ch[i]!='\0';i++)
{
//checking conditions for lower case only u can also implement for uppercase letters
if(ch[i]=='a'||ch[i]=='e'||ch[i]=='i'||ch[i]=='o'||ch[i]=='u')
{
l++;
cout<<"\nvowel is : "<<ch[i]<<" and its position is at : "<<i+1;
}
}
cout<<"\n\nNumber of vowels are in the string is : "<<l;
getch();
}
Output
/*
as we know that there is 5 vowels in our english alphabets.
such as "a,e,i,o,u";
*/
#include<iostream.h>
#include<conio.h>
int main()
{
char ch[25];
int i,l=0;
cout<<"Enter a string:\n";
cin.getline(ch,25);
for(i=0;ch[i]!='\0';i++)
{
//checking conditions for lower case only u can also implement for uppercase letters
if(ch[i]=='a'||ch[i]=='e'||ch[i]=='i'||ch[i]=='o'||ch[i]=='u')
{
l++;
cout<<"\nvowel is : "<<ch[i]<<" and its position is at : "<<i+1;
}
}
cout<<"\n\nNumber of vowels are in the string is : "<<l;
getch();
}
Output
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