Digital Conversion From Binary 2 Octal
#include<iostream.h>
#include<conio.h>
#include<string.h>
#include<math.h>
void main()
{
int ar[10],n,j=0,sum=0,dec,i=0;
cout<<"Enter the binary value:";
cin>>n;
while(n>0)
{
sum=sum+n%10*pow(2,j);
j++;
n=n/10;
}
dec=sum;
while(dec>0)
{
ar[i]=dec%8;
i++;
dec=dec/8;
}
cout<<"octal value is:";
for(int k=i-1;k>=0;k--)
{
cout<<ar[k];
}
getch();
}
#include<conio.h>
#include<string.h>
#include<math.h>
void main()
{
int ar[10],n,j=0,sum=0,dec,i=0;
cout<<"Enter the binary value:";
cin>>n;
while(n>0)
{
sum=sum+n%10*pow(2,j);
j++;
n=n/10;
}
dec=sum;
while(dec>0)
{
ar[i]=dec%8;
i++;
dec=dec/8;
}
cout<<"octal value is:";
for(int k=i-1;k>=0;k--)
{
cout<<ar[k];
}
getch();
}
Output
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